Enter three known values including at least one side to calculate the remaining properties of the triangle.
Triangles are fundamental shapes in geometry with unique properties that make them essential in various mathematical and real-world applications. Here's a comprehensive guide on how to calculate triangle properties:
\( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \)
Where a, b, and c are the side lengths, and A, B, and C are the angles opposite to these sides, respectively.
\( c^2 = a^2 + b^2 - 2ab \cos C \)
This formula relates the lengths of the sides to the cosine of one of the angles.
\( Area = \sqrt{s(s-a)(s-b)(s-c)} \)
Where s is the semiperimeter: \( s = \frac{a + b + c}{2} \)
\( Perimeter = a + b + c \)
\( r = \frac{Area}{s} \)
Where r is the radius of the inscribed circle.
\( R = \frac{abc}{4 \cdot Area} \)
Where R is the radius of the circumscribed circle.
Let's solve a triangle with side a = 4 units, side b = 5 units, and angle C = 60°.
\( c^2 = a^2 + b^2 - 2ab \cos C \)
\( c^2 = 4^2 + 5^2 - 2(4)(5) \cos 60° \)
\( c^2 = 16 + 25 - 40(0.5) = 21 \)
\( c = \sqrt{21} \approx 4.58 \) units
\( \sin A = \frac{a \sin C}{c} = \frac{4 \sin 60°}{4.58} \approx 0.7544 \)
\( A = \arcsin(0.7544) \approx 48.89° \)
\( B = 180° - A - C = 180° - 48.89° - 60° \approx 71.11° \)
\( Perimeter = 4 + 5 + 4.58 = 13.58 \) units
\( s = \frac{13.58}{2} = 6.79 \) units
\( Area = \sqrt{6.79(6.79-4)(6.79-5)(6.79-4.58)} \approx 9.93 \) square units
\( r = \frac{9.93}{6.79} \approx 1.46 \) units
\( R = \frac{4 \cdot 5 \cdot 4.58}{4 \cdot 9.93} \approx 2.31 \) units
This diagram illustrates the triangle from our example, showing how the Law of Sines and Law of Cosines relate the sides and angles of the triangle.